1. Student instructions

  1. Choose one answer for each question.
  2. Complete the test independently.
  3. Work without a calculator for this assessment.
  4. Use scratch paper for calculations.
  5. Give exact answers where appropriate.
  6. If a question takes too long, mark it for review and return to it later.
  7. Check domain restrictions, signs, sequence indices, and units before submitting.

Suggested timing:

  • First attempt: 35 minutes.
  • Review unanswered and uncertain questions: 10 minutes.

Start the timer when you begin Question 1.


2. Test questions

Question 1

Find the domain of:

\[ f(x)=\frac{\sqrt{x+2}}{x-1}. \]

A. [−2, ∞)

B. [−2, 1) ∪ (1, ∞)

C. (−2, 1) ∪ (1, ∞)

D. [−2, 1)


Question 2

Find the range of:

\[ f(x)=(x-3)^2-2,\qquad 1\leq x\leq4. \]

A. [−2, 2]

B. [−2, −1]

C. [−1, 2]

D. [1, 4]


Question 3

Which function is even on its domain?

A. \(f(x)=x^3+x\)

B. \(f(x)=x^2+x\)

C. \(f(x)=x^4-3x^2+2\)

D. \(f(x)=x^3+1\)


Question 4

Let:

\[ f(x)=2x-1,\qquad g(x)=x^2. \]

Find:

\[ f(g(-2)). \]

A. −9

B. 25

C. −7

D. 7


Question 5

A function is defined by:

\[ f(x)= \begin{cases} x+2, & x<1,\\ x^2, & x\geq1. \end{cases} \]

Find:

\[ f(0)+f(1). \]

A. 2

B. 3

C. 4

D. 5


Question 6

Which function has all the following features?

  • Domain: all real numbers.
  • Range: positive real numbers.
  • Passes through (0, 1).
  • Strictly decreasing.
  • Horizontal asymptote: y = 0.

A. \(y=2^x\)

B. \(y=\log_2x\)

C. \(y=\left(\frac12\right)^x\)

D. \(y=-x^2+1\)


Question 7

Solve:

\[ 9^x=27^{x-1}. \]

A. x = 1

B. x = 2

C. x = −3

D. x = 3


Question 8

Solve:

\[ \log_2(x-1)+\log_2(x+1)=3. \]

A. x = 3

B. x = −3

C. x = −3 or x = 3

D. x = 9


Question 9

Solve:

\[ \left(\frac12\right)^x\geq4. \]

A. x ≥ 2

B. x ≤ 2

C. x ≤ −2

D. x ≥ −2


Question 10

Given:

\[ \sin\theta=\frac5{13}, \qquad \frac{\pi}{2}<\theta<\pi, \]

find cos θ.

A. 12/13

B. −12/13

C. −5/13

D. 5/12


Question 11

An arithmetic sequence satisfies:

\[ a_4=11,\qquad a_9=26. \]

Find its general term.

A. aₙ = 3n + 2

B. aₙ = 5n − 9

C. aₙ = 2n + 3

D. aₙ = 3n − 1


Question 12

Find the sum:

\[ 4+7+10+\cdots+31. \]

A. 175

B. 157.5

C. 192.5

D. 350


Question 13

A geometric sequence has:

\[ a_1=5,\qquad r=-2. \]

Find the sixth term.

A. 160

B. −80

C. −160

D. 320


Question 14

Find:

\[ 3+6+12+24+48+96. \]

A. 96

B. 192

C. 381

D. 189


Question 15

A geometric sequence satisfies:

\[ a_2=6,\qquad a_5=162. \]

Find the common ratio.

A. 2

B. 3

C. −3

D. 9


Question 16

A sequence has partial sum:

\[ S_n=n^2+2n, \]

where \(S_n\) is the sum of its first n terms.

Find its nth term.

A. aₙ = n + 2

B. aₙ = 2n − 1

C. aₙ = 2n + 1

D. aₙ = n² + 2


Question 17

Differentiate:

\[ f(x)=2x^3-5x^2+4x-7. \]

A. \(f'(x)=6x^2-10x+4\)

B. \(f'(x)=6x^2-5x+4\)

C. \(f'(x)=2x^2-10x+4\)

D. \(f'(x)=6x^2-10x-7\)


Question 18

For:

\[ f(x)=x^2+\frac3x,\qquad x\neq0, \]

find \(f'(1)\).

A. 5

B. 1

C. −5

D. −1


Question 19

Find the tangent line to:

\[ f(x)=x^2-2x+3 \]

at x = 2.

A. y = 2x + 3

B. y = 2x − 1

C. y = 3x − 3

D. y = 2x − 4


Question 20

A function is differentiable on all real numbers and satisfies:

\[ f'(x)=(x+2)(x-1). \]

On which interval is the function decreasing?

A. (−∞, −2)

B. (1, ∞)

C. (−2, 1)

D. (−∞, 1)


Question 21

Which statement correctly describes:

\[ f(x)=x^3-3x^2? \]

A. It has a local maximum at (0, 0) and a local minimum at (2, −4).

B. It has a local minimum at (0, 0) and a local maximum at (2, −4).

C. It has local maxima at both (0, 0) and (2, −4).

D. It has no stationary points.


Question 22

Find the absolute maximum value of:

\[ f(x)=x^2-4x+1 \]

on the interval [0, 5].

A. −3

B. 1

C. 5

D. 6


Question 23

A rectangle has perimeter 36 meters.

What is its largest possible area?

A. 72 m²

B. 81 m²

C. 36 m²

D. 324 m²


Question 24

A particle’s position is:

\[ s(t)=t^2-6t+5,\qquad 0\leq t\leq5, \]

where position is measured in meters and time in seconds.

Find its total distance traveled over this interval.

A. 5 m

B. 9 m

C. 13 m

D. 4 m


Question 25

A student claims:

Every stationary point is a local maximum or local minimum.

Which function provides a counterexample at x = 0?

A. \(f(x)=x^3\)

B. \(f(x)=x^2\)

C. \(f(x)=-x^2\)

D. \(f(x)=x+1\)


3. Submission check

Before submitting, check that you have:

  • Selected exactly one answer for each question.
  • Applied all domain restrictions.
  • Rejected invalid logarithmic solutions.
  • Used the correct sequence indices and term counts.
  • Distinguished a function value from a derivative value.
  • Checked endpoints where required.
  • Distinguished distance from displacement.

Stop the timer and record your completion time.


4. Instructor answer key

Question Answer Question Answer
1 B 14 D
2 A 15 B
3 C 16 C
4 D 17 A
5 B 18 D
6 C 19 B
7 D 20 C
8 A 21 A
9 C 22 D
10 B 23 B
11 D 24 C
12 A 25 A
13 C — —

5. Answers and explanations

Answer 1: B

The square root requires:

\[ x+2\geq0, \]

so x ≥ −2.

The denominator requires x ≠ 1.

Domain: [−2, 1) ∪ (1, ∞).

Answer 2: A

The squared term is smallest at x = 3:

\[ f(3)=-2. \]

Check the endpoints:

\[ f(1)=2,\qquad f(4)=-1. \]

The function is continuous on the interval.

Range: [−2, 2].

Answer 3: C

For the function in option C:

\[ f(-x)=(-x)^4-3(-x)^2+2=x^4-3x^2+2=f(x). \]

Its domain is symmetric about zero, so it is even.

Answer 4: D

Evaluate the inner function first:

\[ g(-2)=(-2)^2=4. \]

Then:

\[ f(4)=2(4)-1=7. \]

Answer: 7.

Answer 5: B

Since 0 < 1, use the first branch:

\[ f(0)=0+2=2. \]

Since 1 belongs to the second branch:

\[ f(1)=1^2=1. \]

Therefore:

\[ f(0)+f(1)=3. \]

Answer 6: C

An exponential function with base between 0 and 1 is strictly decreasing.

For:

\[ y=\left(\frac12\right)^x, \]

the domain is all real numbers, outputs are positive, the graph passes through (0, 1), and its horizontal asymptote is y = 0.

Answer 7: D

Rewrite using base 3:

\[ 3^{2x}=3^{3x-3}. \]

Therefore:

\[ 2x=3x-3. \]

Answer: x = 3.

Answer 8: A

The original logarithms require x > 1.

Combine:

\[ \log_2\big((x-1)(x+1)\big)=3. \]

Therefore:

\[ x^2-1=8, \]\[ x^2=9. \]

The candidates are −3 and 3, but only 3 satisfies x > 1.

Answer: x = 3.

Answer 9: C

Write 4 using base 1/2:

\[ 4=\left(\frac12\right)^{-2}. \]

The exponential function is decreasing, so:

\[ \left(\frac12\right)^x \geq \left(\frac12\right)^{-2} \]

requires:

\[ x\leq-2. \]

Answer: x ≤ −2.

Answer 10: B

Use:

\[ \sin^2\theta+\cos^2\theta=1. \]

Then:

\[ \cos^2\theta=1-\frac{25}{169} =\frac{144}{169}. \]

Cosine is negative in the second quadrant.

Answer: cos θ = −12/13.

Answer 11: D

There are five steps from the fourth term to the ninth:

\[ 5d=26-11=15. \]

Thus d = 3.

Find the first term:

\[ a_1=11-3(3)=2. \]

Therefore:

\[ a_n=2+3(n-1)=3n-1. \]

General term: aₙ = 3n − 1.

Answer 12: A

Find the number of terms:

\[ 31=4+3(n-1). \]

Thus n = 10.

\[ S_{10}=\frac{10}{2}(4+31)=175. \]

Answer: 175.

Answer 13: C

Use the geometric general term:

\[ a_6=a_1r^5=5(-2)^5=-160. \]

Answer: −160.

Answer 14: D

There are six terms, with first term 3 and ratio 2.

\[ S_6=\frac{3(2^6-1)}{2-1} =3(63)=189. \]

Answer: 189.

Answer 15: B

For a geometric sequence:

\[ a_5=a_2r^3. \]

Therefore:

\[ 162=6r^3, \]\[ r^3=27. \]

Common ratio: r = 3.

Answer 16: C

For n ≥ 2:

\[ a_n=S_n-S_{n-1}. \]

Calculate:

\[ S_{n-1}=(n-1)^2+2(n-1)=n^2-1. \]

Therefore:

\[ a_n=(n^2+2n)-(n^2-1)=2n+1. \]

Check the first term separately:

\[ a_1=S_1=3. \]

The formula also gives 3 when n = 1.

General term: aₙ = 2n + 1.

Answer 17: A

Differentiate each term:

\[ f'(x)=6x^2-10x+4. \]

The derivative of the constant −7 is zero.

Answer 18: D

Differentiate:

\[ f'(x)=2x-\frac3{x^2}. \]

Evaluate:

\[ f'(1)=2-3=-1. \]

Answer: −1.

Answer 19: B

Find the point:

\[ f(2)=4-4+3=3. \]

Find the slope:

\[ f'(x)=2x-2, \]\[ f'(2)=2. \]

The tangent equation is:

\[ y-3=2(x-2). \]

Answer: y = 2x − 1.

Answer 20: C

The derivative is:

\[ f'(x)=(x+2)(x-1). \]

It is negative when the factors have opposite signs:

\[ -2<x<1. \]

Decreasing interval: (−2, 1).

Answer 21: A

Differentiate:

\[ f'(x)=3x^2-6x=3x(x-2). \]

The stationary inputs are 0 and 2.

The derivative signs are:

  • Positive for x < 0.
  • Negative for 0 < x < 2.
  • Positive for x > 2.

Therefore, x = 0 gives a local maximum and x = 2 gives a local minimum.

\[ f(0)=0,\qquad f(2)=8-12=-4. \]

Local maximum point: (0, 0).

Local minimum point: (2, −4).

Answer 22: D

Differentiate:

\[ f'(x)=2x-4. \]

The interior stationary input is x = 2.

Compare its value with both endpoint values:

\[ f(0)=1, \]\[ f(2)=-3, \]\[ f(5)=6. \]

Absolute maximum value: 6, attained at x = 5.

Answer 23: B

Let the sides be x and y:

\[ 2x+2y=36. \]

Therefore:

\[ y=18-x. \]

Area:

\[ A(x)=x(18-x)=18x-x^2, \qquad 0<x<18. \]

Differentiate:

\[ A'(x)=18-2x. \]

The stationary input is x = 9. The derivative changes from positive to negative there.

Then y = 9.

Maximum area: 81 m².

Answer 24: C

Find the velocity:

\[ v(t)=s'(t)=2t-6. \]

It changes from negative to positive at t = 3, so the particle reverses direction there.

Calculate:

\[ s(0)=5, \]\[ s(3)=9-18+5=-4, \]\[ s(5)=25-30+5=0. \]

Total distance:

\[ |-4-5|+|0-(-4)|=9+4=13. \]

Total distance: 13 m.

The displacement is −5 m.

Answer 25: A

For:

\[ f(x)=x^3, \]

we have:

\[ f'(x)=3x^2. \]

At x = 0, the derivative is zero, so the point is stationary.

However, the function increases through the origin. There is no local maximum or minimum.

Option D is not a counterexample because its derivative is 1, so the point is not stationary.


6. Topic diagnosis

Record your score in each area.

Assessment area Questions Available marks Revision focus
Function concepts and properties 1–5 5 Domain, range, parity, composition, and piecewise functions.
Elementary functions 6–10 5 Exponential graphs, equations, inequalities, logarithms, and trigonometry.
Sequences and summation 11–16 6 Common differences, ratios, general terms, finite sums, and partial sums.
Derivatives and applications 17–25 9 Differentiation, tangents, monotonicity, extrema, optimization, and motion.

A total score can hide a weak topic. Check the topic scores as well as the overall result.


7. Interpreting your result

Score Interpretation Next action
22–25 marks: 88–100% Strong performance on this test. Correct mistakes and check topic scores before proceeding.
20–21 marks: 80–84% Meets the overall course target. Complete targeted revision and check topic scores before proceeding.
15–19 marks: 60–76% Understanding is developing, with gaps requiring revision. Review weak topics and complete a fresh assessment.
0–14 marks: 0–56% Foundational revision is required. Revisit the relevant lessons and worked examples before retesting.

Recommended progression criteria

Before proceeding to the next module, aim to satisfy all of the following:

  • Overall score: At least 20 out of 25.
  • Function concepts: At least 3 out of 5.
  • Elementary functions: At least 3 out of 5.
  • Sequences and summation: At least 4 out of 6.
  • Derivatives and applications: At least 6 out of 9.
  • Corrections: Explain and independently solve every missed question.

Correct guesses should also be reviewed. Repeating the same test after reading its solutions checks correction, but a fresh set of questions gives better evidence of independent mastery.


8. Post-test correction task

For each incorrect or guessed answer, write:

  1. Question number.
  2. My original method.
  3. Why my answer was wrong or uncertain.
  4. The correct method and solution.
  5. A check that would prevent the same mistake.

Classify the error as one of the following:

  • Concept misunderstanding.
  • Incorrect method selection.
  • Algebra or arithmetic error.
  • Missed domain restriction.
  • Incorrect sign.
  • Sequence indexing or term-count error.
  • Misreading the requested quantity.
  • Time-management problem.

Module completion task: Finish the corrections, revise weak areas, and meet the progression criteria before starting the next module.